Question

rationalise the denominator of3/√7+√5​

Answer 1

3/(root 7 + root 5)

=3 *( root 7 - root 5) /( root 7 + root 5)(root 7 - root 5)

=3*(root 7- root 5)/ (root 7)^2 - ( root 5)^2

= 3*(root 7- root 5) / 7-5

=3*(root7 - root 5)/2.

Answer 2

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$\huge{\mathfrak\red{Here \:is \:your \:answer}}$

$\huge{\mathcal\pink{Question}}$

Rationalise the denominator of3/√7+√5.

$\huge{\mathcal\pink{Solution}}$

Given,

Rationalise the denominator = 3/√7+√5

So, = 3 / (√7 + √5

= 3 × (√7 - √5) / √7)^2 - (√5)^2

= 3 × (√7 - √5) / 7 - 5

= 3 × (√7 - √5) / 2

Answer is 3 × (√7 - √5) / 2.

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