Question

rationalise the denominator ...please full explanation bta do answer...​

Answer 1

Answer:

Hey !

Here is your answer !! (:

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➡ 5 / √ 7 - √2

➡ 5 × ( √7 + √2 ) / ( √7 - √2 ) ( √7 + √2 )

➡ 5 × (√ 7 + √2 ) / ( √7)2 - (√2)2

➡ 5 × ( √7 + √2 ) / 7 - 2

➡ 5 × ( √7 + √2 ) / 5

➡ √ 7 + √ 2

Hope it helps you !! (:

Step-by-step explanation:

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Answer 2

Answer:

$=>\sqrt{7}+ \sqrt{2}$

Step-by-step explanation:

$Since\; the\; denominator = \sqrt{7}- \sqrt{2} \;, its\; rationalizing \;factor=\sqrt{7} +\sqrt{2}$

∴$\frac{5}{\sqrt{7}- \sqrt{2} } =\frac{5}{\sqrt{7}- \sqrt{2}} *\frac{\sqrt{7}+ \sqrt{2} }{\sqrt{7} +\sqrt{2} }$

          $=\frac{5(\sqrt{7}+ \sqrt{2}) }{7-2}$

         [∵$(\sqrt{7}- \sqrt{2})( \sqrt{7}+ \sqrt{2} )=(\sqrt{7} )^{2} -(\sqrt{2} )^{2} =7-2=>5$]

$=\frac{5(\sqrt{7} +\sqrt{2} )}{5} => \sqrt{7}+ \sqrt{2}$

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