Question

rationalise the denominator question 91

Answer 1

Solution:

1/(1+√2-√3)

multiply numerator and denominator by (1+√2+√3),

=(1+√2+√3)/[(1+√2-√3)(1+√2+√3)]

= (1+√2+√3)/[(1+√2)²-(√3)²]

= (1+√2+√3)/[1+2+2√2-3]

= (1+√2+√3)/(2√2)

Multiply numerator and denominator by √2 , we get

=[√2(1+√2+√3)]/(2√2×√2)

= [√2+2+√6]/4

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