Question

Rationalise the denominator

$\frac{ \sqrt{2} }{ \sqrt{7} - \sqrt{3} }$

Answer 1

Hola Mate!!

Your answer :-

$= > \frac{ \sqrt{2} }{ \sqrt{7} - \sqrt{3} } \\ \\ = > \frac{ \sqrt{2} }{ \sqrt{7} - \sqrt{3} } \times \frac{ \sqrt{7} + \sqrt{3} }{ \sqrt{7} + \sqrt{3} } \\ \\ = > \frac{ \sqrt{2}( \sqrt{7} + \sqrt{3}) }{ {( \sqrt{7}) }^{2} - {( \sqrt{3} )}^{2} } \\ \\ = > \frac{ \sqrt{14} + \sqrt{6} }{7 - 3} \\ \\ = > \frac{ \sqrt{14} + \sqrt{6} }{4}$

☆ Hope it helps ☆

Answer 2

Hey mate!!

Here's your answer!!

It's in the pic.
Lemme know in case of any doubt.

Hope it helps!!
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