Question

Rationalise the denominators

Answer 1

3/√3+√5-√2=√3-√5+√2/√3-√5+√2
=(3)^2-(5)^2

Answer 2

$\frac{1}{ \sqrt{7} + \sqrt{6} - \sqrt{13} } \times \frac{ \sqrt{7} + \sqrt{6} + \sqrt{13} }{ \sqrt{7} + \sqrt{6} + \sqrt{13} } \\ \frac{ \sqrt{7} + \sqrt{6} + \sqrt{13} }{ {( \sqrt{7} + \sqrt{6} )}^{2} - { (\sqrt{13}) }^{2} } \\ \frac{ \sqrt{7} + \sqrt{6} + \sqrt{13} }{7 + 6 + 2 \sqrt{42} - 13} \\ \frac{ \sqrt{7} + \sqrt{6} + \sqrt{13} }{2 \sqrt{42} }$
follow the same process to each of the question