Rationalise the denominators of the following
question 1) 13/√5
2) 6+√5/6-√5
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To rationalize a denominator with single value, what you have to do it is multiply both numerator and denominator with the number itself.
so here, multiply with 5
1)
= (13 x √5) ÷ √5 x √5
= 13√5 ÷ 5
= 13√5/5
2)
here multiply with additive inverse, = (6+√5)
(6+√5)(6+√5) / (6-√5)(6+√5)
=(36 + 5) / (36-5)
= 41/31
Hope it helps,
Byeeee
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