Math, asked by niloferbano60, 5 months ago

rationalise the denominetor of 4√5/√7-√3​

Answers

Answered by TheWonderWall
2

Answer:

 \frac{4 \sqrt{5} }{ \sqrt{7}  -  \sqrt{3} }  \\  \\  =  \frac{4 \sqrt{5} }{ \sqrt{7}  -  \sqrt{3} }  \times  \frac{ \sqrt{7}  +  \sqrt{3} }{ \sqrt{7} +  \sqrt{3}  }  \\  \\  =  \frac{4 \sqrt{35}  + 4 \sqrt{15} }{ {( \sqrt{7} )}^{2}  -  {( \sqrt{3} )}^{2} }  \\  \\  =  \frac{4 \sqrt{35} + 4 \sqrt{15}  }{7 - 3}  \\  \\  =  \frac{4( \sqrt{35} +  \sqrt{15} ) }{4}  \\  \\  =  \sqrt{35}  +  \sqrt{15}

hope this much helps uh ❣️

Answered by AKKI08SIDDARTH
2

Hope it's Helps to u ✌️✌️

 \sqrt{35}  +  \sqrt{15}

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