Question

rationalise the dinominator
$16 \ \sqrt{14 - 5}$
​

Answer 1

Answer:

the answer is :

$\sqrt{41} + 5$

Step-by-step explanation:

$\frac{16}{ \sqrt{41} - 5 } = \frac{16}{ \sqrt{41} - 5} \times \frac{ \sqrt{41} + 5 }{ \sqrt{41} + 5 } \\ = > \frac{16( \sqrt{41} + 5)}{ { \sqrt{41} }^{2} - {5}^{2} } \\ = > \frac{16( \sqrt{41} + 5) }{41 - 25} \\ = > \frac{16( \sqrt{41} + 5)}{16} \\ = \sqrt{41} + 5$

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