Question

rationalise the following
$\frac{ \sqrt{2 } + 1 }{ \sqrt{3} }$

Answer 1

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$(\frac{ \sqrt{2} + 1 }{ \sqrt{3} } \: \times \frac{ \sqrt{3} }{ \sqrt{3}})$

$=>\frac{ \sqrt{6} + \sqrt{3} }{ \sqrt{3} } \:$

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Answer 2

Solution:

$\boxed{\sf{ \frac{ \sqrt{2} + 1 }{ \sqrt{3} }}}$

$\implies$ $\sf{ \frac{ \sqrt{2} + 1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }}$

$\implies$ $\sf{ \frac{( \sqrt{2} + 1) \sqrt{3} }{ \sqrt{3} \sqrt{3} }}$

$\implies$ $\sf{ \frac{ \sqrt{6} + \sqrt{3} }{3}}$

$\implies$ $\sf{ 1.39385}$

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