Math, asked by sidra1784, 1 year ago

Rationalise this question

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Answered by shashankavsthi
1

 \frac{ \sqrt{3} + 1 }{ \sqrt{3}  - 1}  \\ multiplying \: nr. \: and \: deno. \\ by \:  \sqrt{3}  + 1 \\ then \\  \frac{ \sqrt{3}  + 1}{ \sqrt{3}  - 1}  \times  \frac{ \sqrt{3} + 1 }{ \sqrt{3}  + 1}  \\  \frac{3 + 1 + 2 \sqrt{3} }{3 - 1}  \\  \frac{4 + 2 \sqrt{3} }{2}  \\  \frac{(2)(2 +  \sqrt{3)} }{2}  \\ 2 +  \sqrt{3}
so

a=2
b=1
Answered by arunimakon
0
There's your Answer, hope it helps
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