Question

Rationalish the denominatoes 1/√7-√6
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Answer 1

QUESTION:

Rationalise the Denominator -

$\frac{1}{ \sqrt{7} - \sqrt{6} }$

SOLUTION:

$= > \frac{1}{ \sqrt{7} - \sqrt{6} } \\ \\ = > \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } = \frac{ \sqrt{7} + \sqrt{6} }{( \sqrt{7}) {}^{2} + ({ \sqrt{6} )}^{2} } \\ \\ = > \frac{ \sqrt{7} + \sqrt{6} }{7 + 6} = \frac{ \sqrt{7} + \sqrt{6} }{13}$

Therefore, the Rationalised Form of 1 / √7 - √6 is √7 + √6 / 13

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