Question

rationalising denominator

Answer 1

Heya!

Here is yr answer.....


$= > \frac{1}{4 + \sqrt{5} } \\ \\ = > \frac{1}{4 + \sqrt{5} } \times \frac{4 - \sqrt{5} }{4 - \sqrt{5} } \\ \\ = > \frac{4 - \sqrt{5} }{16 - 5} \\ \\ = > \frac{4 - \sqrt{5} }{11}$


Hope it hlpz..

Answer 2

Let see your answer !!!!!

$\frac{1}{4 + \sqrt{5} } \\ \\ = \frac{1 \times (4 - \sqrt{5}) }{(4 + \sqrt{5}) \times (4 - \sqrt{5}) } \\ \\ = \frac{4 - \sqrt{5} }{(4) ^{2} - ( \sqrt{5}) ^{2} } \\ \\ = \frac{4 - \sqrt{5} }{16 - 5} \\ \\ = \frac{4 - \sqrt{5} }{11}$






Thanks :)))))