Question

rationalising the denominator 1/2underoot3-under root 7​

Answer 1

ANSWER IS

$\frac{\sqrt[2]{3}+\sqrt{7} }{5}$

QUESTION IS

rationalising the denominator $\frac{1}{\sqrt[2]{3}-\sqrt{7} }$

STEP BY STEP ANSWER

$=\frac{1}{\sqrt[2]{3}-\sqrt{7} }*\frac{\sqrt[2]{3}+\sqrt{7} }{\sqrt[2]{3}+\sqrt{7} }$  

$=\frac{\sqrt[2]{3}+\sqrt{7} }{(\sqrt[2]{3)}^{2}-(\sqrt{7) }^{2} }$

$=\frac{\sqrt[2]{3}+\sqrt{7} }{12-7}$  

$=\frac{\sqrt[2]{3}+\sqrt{7} }{5}$

HOPE IT HELP YOU