Question

rationalising the denominator 2/3+√2​

Answer 1

Given:

$\frac{2}{3 + \sqrt{2} }$

Solution:

On multiplying both numerator and denominator with (3–√2) gives:

$> > \frac{2}{3 + \sqrt[]{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} }$

$> > \frac{2(3 - \sqrt{2} )}{(3) {}^{2} -( \sqrt{2} ) {}^{2} }$

$> > \frac{6 - 2 \sqrt{2} }{9 - 2}$

$> > \frac{6 - 2 \sqrt{2} }{7}$

So,

$\frac{2}{3 + \sqrt{2} } = \frac{6 - 2 \sqrt{2} }{7}$

Answer 2

Answer:

Hey Buddy here's ur answer