Question

rationalising the denominator of 7/3√3 -2√2

Answer 1

$\frac{7}{3 \sqrt{3 } - 2 \sqrt{2} } \times \frac{3 \sqrt{3} + 2 \sqrt{2} }{3 \sqrt{3} + 2 \sqrt{2} } = \frac{21 \sqrt{3} + 14 \sqrt{2} }{27 - 8} = \frac{21 \sqrt{3} + 14 \sqrt{2} }{19}$

Answer 2

REFERS TO THE ATTACHMENT ---------›