Question

rationalize 2+√3/2+√2​

Answer 1

Answer:

2-√2+√3-√6 is the correct answer

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

$\frac{2 + \sqrt{3} }{2 + \sqrt{2} }$

$\frac{2 + \sqrt{3} }{2 + \sqrt{2} } \times \frac{2 - \sqrt{2} }{2 - \sqrt{2} }$

$\frac{(2 + \sqrt{3} )(2 - \sqrt{2} )}{(2 + \sqrt{2} )(2 - \sqrt{2} )}$

$\frac{2(2 - \sqrt{2} )+ \sqrt{3}(2 - \sqrt{2} ) }{ {2}^{2} - ( \sqrt{2}) ^{2} }$

$\frac{4 - 2 \sqrt{2} + 2 \sqrt{3} - \sqrt{6} }{4 - 2}$

$\frac{4 - 2 \sqrt{2} + 2 \sqrt{3} - \sqrt{6} }{ 2}$

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