Math, asked by aliasgar19, 11 months ago

rationalize
5+√5/√5+√3= 1/2a+3b​

Answers

Answered by sujalkumarsaini
1

Answer:

(5+√5/√5+√3)×(5-√3/√5-√3)=1/2a+3b

{(5+√5)(5-√3)}/5-3=1/2a+3b

(25-5√3+5√5-√15)/2=1/2a+3b

therefore,

(25-5√3+5√5-√15)/2+3×0=1/2a+3b

hence,

a=25-5√3+5√5-√15

b=0

Answered by royalshivam04826
1

Answer:

 \sqrt{3}   - 6b + 5 = 0

Step-by-step explanation:

  • = 5+√5/√5+√3=1/2a+3b
  • = 5+1+√3=1+6ab/2a
  • = ( 6+√3 ) 2a = 1+6ab
  • = 12a+2√3a - 6ab - 1 = 0
  • = 2a(6+√3-6b-1)=0
  • = 5+√3-6b=0
  • = √3-6b+5=0
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