Math, asked by sowmiya261, 8 months ago

rationalize : 5 / root 3 - root 5​

Answers

Answered by Glorious31
4

Answer :

\tt{ \dfrac{5}{\sqrt{3} - \sqrt{5}}}

For rationalising the denominator ; first we will check the sign in the given rational number .

In the case of the given number its (-) so ; we will multiply it's positive form with both the numerator and the denominator.

\tt{ \dfrac{5}{\sqrt{3} - \sqrt{5}} \times \dfrac{\sqrt{3}+\sqrt{5}}{\sqrt{3} + \sqrt{5}}}

If we carefully observe the denominators ; they are in the \tt{ (a+b) (a-b) } identity where (a) in this condition is \tt{ \sqrt{3}} and (b) is \tt{ \sqrt{5}}.

The expansion of \tt{ (a+b) (a-b) } identity is \tt{ {a}^{2} - {b}^{2}}.

So we will put the same identity for solving the problem.

If we do so ; it gives us :

\tt{ \dfrac{5 \times \sqrt{3} + \sqrt{5}}{{(\sqrt{3})}^{2} + {(\sqrt{5})}^{2}}}

When further simplified gives us :

\tt{ \dfrac{5\sqrt{3+5}}{3 - 5}}

\large{\boxed{\tt{ \implies \dfrac{5\sqrt{3+5}}{-2}}}}

Answered by SaYwHyDudE
0

This is the answer you should follow to be top in maths

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