Question

Rationalize : 6 / root 12 - root 3 ! Pls show wid steps , got stuck in between !

Answer 1

$\frac{6}{\sqrt{12}-\sqrt3}=\frac{6}{\sqrt{4\times3}-\sqrt3}=\frac{6}{\sqrt4\times\sqrt3-\sqrt3}=\frac{6}{2\sqrt3-\sqrt3}=\frac{6}{\sqrt3}\times\frac{\sqrt3}{\sqrt3}=\frac{6\sqrt3}{3}=2\sqrt3$

Answer 2

[tex] \frac{6}{ \sqrt{12} - \sqrt{3} } =\frac{6 \sqrt{12} + \sqrt{3} }{ (\sqrt{12} - \sqrt{3})( \sqrt{12} + \sqrt{3}) } = \frac{ 6(\sqrt{12}+ \sqrt{3} ) }{(12-3)} = \frac{ 6(\sqrt{12}+ \sqrt{3} )}{9} = \frac{2\sqrt{12}+ \sqrt{3} }{3} (ans) [/tex]