Math, asked by ks8209671345, 1 month ago

rationalize and explain​

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Answers

Answered by anindyaadhikari13
4

Solution:

Given to Rationalise,

 \tt =  \dfrac{1}{1 - 2\sqrt{3} }

Multiplying both numerator and denominator by the conjugate of denominator, we get,

 \tt =  \dfrac{1 \times (1 + 2 \sqrt{3} )}{(1 - 2\sqrt{3})(1 + 2 \sqrt{3}) }

 \tt =  \dfrac{1 + 2 \sqrt{3}}{(1) ^{2} - (2\sqrt{3})^{2}}

 \tt =  \dfrac{1 + 2 \sqrt{3}}{1-12}

 \tt =  \dfrac{1 + 2 \sqrt{3}}{ -11}

 \tt =  \dfrac{ - 1  - 2 \sqrt{3}}{11}

So, after rationalisation, we get,

 \tt =  \dfrac{ - 1  - 2 \sqrt{3}}{11}

Answer:

  •  \tt \dfrac{ - 1  - 2 \sqrt{3}}{11}

Concept:

  • Rationalisation: This is the process to remove the surds from the denominator part of a fraction. To do this, we have to multiply both numerator and denominator part of the fraction with the conjugate of denominator.
  • For example, here conjugate of 1 - 2√3 is 1 + 2√3.

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