Question

rationalize denominator √3-1/√3+1=a-√3b..... find the value of a and b​

Answer 1

hope this is your answer

Answer 2

$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } = a - \sqrt{3} b \\ \\ \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1} = a - \sqrt{3} b \\ \\ \frac{3 + 1 - 2 \sqrt{3} }{3 - 1} = a - \sqrt{3} b \\ \\ 2 - \sqrt{3} = a - \sqrt{3} b \\ \\ comparing \: both \: sides \\ a = 2 \: \: \: \: \: \: b = 1$