Question

Rationalize denominator of 1 by 7+3 root 2

Answer 1

Heya !!!



1/ 7 + 3 root 2




=> 1/ 7 + 3 root 2 × 7 - 3 root 2 / 7 - 3 root 2





=> 1 ( 7 - 3 root 2) / ( 7 + 3 root 2) ( 7 - 3 root 2)




=> 7 - 3 root 2 / ( 7)² - (3 root 2)²




=> 7 - 3 root 2 / 49 - 18



=> 7 - 3 root 2/ 31






★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★

Answer 2

hiii!!!

here's Ur answer...

$we \: have \: to \: rationalize \: \frac{1}{7 + 3 \sqrt{2} } \\ \\ = \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} } \\ \\ = \frac{1(7 - 3 \sqrt{2} )}{(7 + 3 \sqrt{2} ) + (7 - 3 \sqrt{2} )} \\ \\ = \frac{7 - 3 \sqrt{2} }{ {(7)}^{2} - {(3 \sqrt{2} )}^{2} } \\ \\ = \frac{7 - 3 \sqrt{2} }{49 - 18} \\ \\ = \frac{7 - 3 \sqrt{2} }{31}$

hope this helps..!!