Question

rationalize denominator square root 3 minus one upon square root 3 + 1

Answer 1

$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1} \\ = \frac{( \sqrt{3} - 1)( \sqrt{3} - 1) }{( \sqrt{3} + 1)( \sqrt{3} - 1) } \\ = \frac{( { \sqrt{3} - 1) }^{2} }{ {( \sqrt{3}) - ( 1) }^{2} } \\ = \frac{3 + 1 - 2 \sqrt{3} }{3 - 1} \\ = \frac{4 - 2 \sqrt{3} }{2} \\ = 2 - \sqrt{3}$

Answer 2

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