Question

Rationalize the denominaror of 1/√6+√5-√11



Answer plz ​

Answer 1

Answer:

1/√6+√5-√11

1/√6+√5/1-√11/1

LCM of denominator is √6

(1+√5-√11) ÷√6

1+√5-√11/√6 ×-1-√5+√11/√6

multiply

(1)²-(√5)²-(√11)²÷6

1-5-11÷6

-15/6

-5/2 answer

Answer 2

Step-by-step explanation:

= 1/√6+√5-√11

=[1/√6+√5-√11][(√6+√5)+√11/(√6+√5)+√11]

=(√6+√5)+√11/(√6+√5)^2-(√11)^2

=√6+√5+√11/[(√6)^2+(√5)^2+2×√6×√5]-11

=√6+√5+√11/(6+5+2√30)-11

=√6+√5+√11/11+2√30-11

=√6+√5+√11/2√30

again,

[√6+√5+√11/2√30] [√30/√30]

[√30(√6+√5+√11)]/[2√30*√30]

(6√5+5√6+√330)/2*30

6√5+5√6+√330/60