Question

rationalize the denominator 1/1+√2+√3

Answer 1

Answer:

Step-by-step explanation:

Given 1/[(1 + √2) - √3 ] rationalise the denominator ⇒ [(1 + √2) + √3 ] / [(1 + √2) - √3 ] [(1 + √2) + √3 ] ⇒ [(1 + √2) + √3 ] / [(1 + √2)2 - 3 ] ⇒ [(1 + √2) + √3 ] / [2√2 ] rationalise the denominator with √2 ⇒ √2[(1 + √2) + √3 ] / 4 ⇒ (√2 + 2 + √6 ] / 4

Answer 2

Use (1+√2) as A and (√3) as B.

Then use A^2-B^2 = (A+B)(A-B)