Math, asked by IndianArmyGirl, 7 months ago

rationalize the denominator
1/√3-√2

Answers

Answered by Anonymous

Question;

rationalize the denominator

1/√3-√2

Answer;

$\bf \: 1) \frac{1}{ \sqrt{3} - \sqrt{2} }$

$\bf \implies \: \frac{1}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$\bf \implies \: \frac{ \sqrt{3} + \sqrt{2} }{3 - 2}$

$\bf \implies \: \frac{ \sqrt{3} + \sqrt{2} }{1}$

$\bf \implies \: \sqrt{3} + \sqrt{2}$

Answered by Anonymous

Answer:

$\frac{1}{ \sqrt{3} - \sqrt{2} } \\ \\ \frac{1}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ \frac{ \sqrt{3} + \sqrt{2} }{3 - 2} \\ \\ = \frac{ \sqrt{3} - \sqrt{2} }{1} \\ \\ \sqrt{3} \sqrt{2}$

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