rationalize the denominator 1÷√5+√2 and subtract it from √5-√2
Answers
Answered by
68
Hi there.
Your answer is :-
1/√5 + √2
1( √5 - √2 )/ ( √5 + √2 )×( √5 - √2 )
√5 - √2/ 5 - 2
√5 - √2/ 3
Now subtract √5 - √2
√5 - √2 - √5 - √2 / 3
3√5 - 3√2 - √5 + √2 / 3
2√5 - 2√2 / 3 ( Ans )
Thank You
Your answer is :-
1/√5 + √2
1( √5 - √2 )/ ( √5 + √2 )×( √5 - √2 )
√5 - √2/ 5 - 2
√5 - √2/ 3
Now subtract √5 - √2
√5 - √2 - √5 - √2 / 3
3√5 - 3√2 - √5 + √2 / 3
2√5 - 2√2 / 3 ( Ans )
Thank You
siddhartharao77:
Nice answer Graxx!
Answered by
18
plz mark me as brainlist and follow me.
5 - 2 = 3.
(root2)^2 = 2. u wrote 4.
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