Question

rationalize the denominator 1+√7/1-√7

Answer 1

1+√7/1-√7×1+√7/1+√7=2√7-8/6 is the right answer
hope it's help.......

Answer 2

Hey friend,
Here is the answer you were looking for:
$\frac{1 + \sqrt{7} }{1 - \sqrt{7} } \\ \\ on \: rationalizing \: the \: denominator \: we \: get \\ \\ = \frac{1 + \sqrt{7} }{1 - \sqrt{7} } \times \frac{ 1 + \sqrt{7} }{1 + \sqrt{7} } \\ \\ using \: the \: identities \\ {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ (a + b)(a - b) = {a}^{2} - {b}^{2} \\ \\ \frac{ {(1)}^{2} + {( \sqrt{7} )}^{2} + 2 \times 1 \times \sqrt{7} }{ {(1)}^{2} - {( \sqrt{7}) }^{2} } \\ \\ = \frac{1 + 7 + 2 \sqrt{7} }{1 - 7} \\ \\ = \frac{8 + 2 \sqrt{7} }{ - 6} \\ \\ = \frac{ - 8 - 2 \sqrt{7} }{6} \\ \\ = \frac{ - 4 - \sqrt{7} }{3}$


Hope this helps!!!!

@Mahak24

Thanks....
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