Question

Rationalize the denominator 1 by √7- √6

Answer 1

Answer:

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Rationalising the denominator of:

$\frac{1}{ \sqrt{7} - \sqrt{6} }$

$= \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} }$

$= \frac{ \sqrt{7} + \sqrt{6} }{( { \sqrt{7} })^{2} - ( { \sqrt{6} })^{2} }$

$= \frac{ \sqrt{7} + \sqrt{6} }{7 - 6}$

$= \sqrt{7} + \sqrt{6}$

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Answer 2

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