Question

Rationalize the denominator 1 ÷ root 7+root 6 -root 13

Answer 1

1/√7+√6-√13
(1/√7 +√6-√13)* (√7-√6+√13/√7-√6 +√13)
√7-√6+√13/7-6-13
√7-√6+√13/1-13
√6-√6+√13/-12 answer ✅
If my answer helps you please mark my answer as brainliest please

Answer 2

Hey dear!


Here is yr answer.....


$= > \frac{1}{ \sqrt{7} + \sqrt{6} - \sqrt{13} } \\ \\ = > \frac{1}{ \sqrt{7} + \sqrt{6} - \sqrt{13} } \times \frac{ \sqrt{7} + \sqrt{6} + \sqrt{13} }{ \sqrt{7} + \sqrt{6} + \sqrt{13} } \\ \\ = > \frac{ \sqrt{7} + \sqrt{6} + \sqrt{13} }{7 + \sqrt{42} + \sqrt{91} + \sqrt{42} + 6 + \sqrt{78} - \sqrt{91} - \sqrt{78} - 13 } \\ \\ = > \frac{ \sqrt{7} + \sqrt{6} + \sqrt{13} }{2 \sqrt{42} }$

Hope it hlpz...