Math, asked by arumishra, 1 year ago

rationalize the denominator 1 upon 3 + under root 3​

Answers

Answered by happyrai
1

 \frac{1}{3 +  \sqrt{3} }

 \frac{1}{3 +  \sqrt{3} }  \times  \frac{3 -  \sqrt{3} }{3 -  \sqrt{3} }

 \frac{3 -  \sqrt{3} }{ {3}^{2}  -  \sqrt{3 {}^{2} } }

 \frac{3 - \sqrt{3} }{9 - 3}

 \frac{3 -  \sqrt{3} }{6}


happyrai: please mark as brainlist
arumishra: ok
arumishra: hii
Similar questions