Rationalize the denominator
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Hi ,
It is given that ,
1/( √2 + √3 + √5 )
=(√2+√3-√5)/[(√2+√3+√5)(√2+√3-√5)
= (√2+√3-√5)/[(√2 + √3 )² - ( √5 )² ]
= (√2 + √3 - √5 )/[2 + 3 + 2√6 - 5 ]
= ( √2 + √3 - √5 )/ ( 2√6 )
= [√6(√2+√3 - √5 )]/( 2√6 ×√6 )
= ( 2√3 + 3√2 - √30 )/ 12
I hope this helps you.
: )
It is given that ,
1/( √2 + √3 + √5 )
=(√2+√3-√5)/[(√2+√3+√5)(√2+√3-√5)
= (√2+√3-√5)/[(√2 + √3 )² - ( √5 )² ]
= (√2 + √3 - √5 )/[2 + 3 + 2√6 - 5 ]
= ( √2 + √3 - √5 )/ ( 2√6 )
= [√6(√2+√3 - √5 )]/( 2√6 ×√6 )
= ( 2√3 + 3√2 - √30 )/ 12
I hope this helps you.
: )
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6
Hi,
Please see the attached file!.
Thanks
Please see the attached file!.
Thanks
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