Rationalize the denominator
2/5+3root2
Answers
Answered by
1
Answer:
5−325+32=a+b25−325+32×5+325+32=a+b252−(3)2(5+32)=a+b225−325+3+103=a+b22228+103=a+b2a=2228andb=2210a=1114andb=115
Answered by
1
Answer:
We rationalise the denominator of (
3
2
−
5
5
2
−
3
) by multiplying its rationalising factor (3
2
+
5
) in the numerator and denominator as follows:
3
2
−
5
5
2
−
3
×
3
2
+
5
3
2
+
5
=
(3
2
−
5
)(3
2
+
5
)
(5
2
−
3
)(3
2
+
5
)
=
(3
2
)
2
−(
5
)
2
5
2
(3
2
+
5
)−
3
(3
2
+
5
)
=
(9×2)−5
(5×3
2×2
)+(5
2×5
)−(3
3×2
)−(
3×5
)
=
18−5
15
4
+5
10
−3
6
−
15
=
13
(15×2)+5
10
−3
6
−
15
=
13
30+5
10
−3
6
−
15
Hence,
3
2
−
5
5
2
−
3
=
13
30+5
10
−3
6
−
15
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