Question

rationalize the denominator : 2/√7-√6​

Answer 1

Answer:

$2\sqrt{7} + 2\sqrt{6}$

Step-by-step explanation:

2/$\sqrt{7}$-$\sqrt{6}$

= $\frac{2}{\sqrt{7}-\sqrt{6} }$  x $\frac{\sqrt{7}+\sqrt{6} }{\sqrt{7}+\sqrt{6} }$

= $\frac{2(\sqrt{7}+\sqrt{6} ) }{\sqrt{7}^{2}- \sqrt{6}^{2} }$

= $\frac{2\sqrt{7}+ 2\sqrt{6} }{7-6}$

= $2\sqrt{7} + 2\sqrt{6}$