Math, asked by lucky432, 1 year ago

rationalize the denominator (2root 35 - root 3) /3root 7-5root 35

Answers

Answered by BrainlyMOSAD
4
here is u r answer
..
2√35_√3/ 3√7_5√35× 3√7+5√35/3√7+5√35
Answered by sk0768173gmailcom
5

 \frac{2 \sqrt{35 } -  \sqrt{3}  }{3 \sqrt{7} - 5 \sqrt{35}  }  \\   = \frac{(2 \sqrt{35} -  \sqrt{3})(3 \sqrt{7} + 5 \sqrt{35}    }{(3 \sqrt{7} - 5 \sqrt{35})(3 \sqrt{7}  + 5 \sqrt{35} )  }  \\  = \frac{42 \sqrt{5} + 350 - 3 \sqrt{21} - 5 \sqrt{105}   }{63 - 25 \times 35}
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