Question

rationalize the denominator 3 + root 2/ 3 - root 2 = a+ b root 2

Answer 1

Answer:

a=3,

b= 1 - root3 / root3

Answer 2

Answer:

Hope it helps you mate..

:)

Step-by-step explanation:

$\frac{3 + \sqrt{2} }{3 - \sqrt{2}} = a + b \sqrt{2}\\\\\frac{3 + \sqrt{2} }{3 - \sqrt{2}} * \frac{3 +\sqrt{2} }{3 + \sqrt{2}} = a + b \sqrt{2}\\\\\frac{(3+\sqrt{2})^{2} }{(3)^{2} - (\sqrt{2}^{2})} = a + b \sqrt{2}\\\\\frac{3^2 + 6\sqrt{2} + \sqrt{2}^{2} }{9-2} = a + b \sqrt{2}\\\\\frac{9 + 6\sqrt{2} + 2 }{7} = a + b \sqrt{2}\\\\\frac{11+ 6\sqrt{2}}{7} = a + b \sqrt{2}$