Math, asked by Anonymous, 1 year ago

rationalize the denominator

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Answered by BrainlyQueen01
6
hey mate!!

here's ur answer:-)

[ I would have solved on paper but right now I don't have a pen in my hand so...]

 \frac{7 +  \sqrt{3} }{7 -  \sqrt{3} }   \\  \\  \frac{7 +  \sqrt{3} }{7 -  \sqrt{3} } \times  \frac{7 +  \sqrt{3} }{7  +   \sqrt{3} }  \\  \\  \frac{(7 +  \sqrt{3}) {}^{2}  }{(7) {}^{2} - ( \sqrt{3} ) {}^{2}  }  \\  \\  \frac{7 {}^{2} + 2 \times 7 \times  \sqrt{3}  + ( \sqrt{3}) {}^{2}   }{49 - 3}  \\  \\  \frac{49 + 14 \sqrt{3} + 3 }{46}  \\  \\  \frac{52 + 14 \sqrt{3} }{46}  \\  \\  \frac{2(26 + 7 \sqrt{3}) }{46}  \\  \\  \frac{26 + 7 \sqrt{3} }{23}


hope it helps✌✌

#thankyou....☺☺
Answered by Preitika
7

Check ur answer !!

P.S : I was getting bored

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