rationalize the denominator
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5√3÷ √31-√6 × √31 + √6÷√31+√6
in numerator,
5√3×√31 + √6= 5√3×31+√6×3
5√93+√18
now in denominator,
√31-√6×√31+√6
(√31)²-(√6)² { by identity (a+b)(a-b)= a²-b²
31-6= 25
5√93+√18 / 25
we can cancle out 25by 5 then the answer is √93+√18/5
hope it will help u frnd
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