Math, asked by maheshbasambekar9273, 11 months ago

rationalize the denominator √5-√3÷√5+√3​

Answers

Answered by harnoor92
3

Answer:

 \frac{ \sqrt{5}  -  \sqrt{3} }{ \sqrt{5} +  \sqrt{3}  }  \times  \frac{ \sqrt{5}  -  \sqrt{3} }{ \sqrt{5}  -  \sqrt{3} }  \\   \frac{ \sqrt{5}( \sqrt{5}  -  \sqrt{3}) -  \sqrt{3}  ( \sqrt{5}  -  \sqrt{3} )} { { \sqrt{5} ^{2}  -  { \sqrt{3} }^{2}  }^{} }  \\  \frac{5 -  \sqrt{15} -  \sqrt{15}   + 3}{ { \sqrt{5} }^{2}  -  \sqrt{3 ^{2} } }  \\  \frac{5 - 2 \sqrt{15}  + 3}{5 - 3}  \\  \frac{8 - 2 \sqrt{15} }{2} \\   \frac{2(4 -  \sqrt{15} )}{2}  \\ 4 -  \sqrt{15}

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