Question

rationalize the denominator
6-4√3÷6+4√3​

Answer 1

Step-by-step explanation:

Given: $\frac{6-4\sqrt{3} }{6+4\sqrt{3} }$

To find: rationalized denominator

Solution: To rationalize, we will multiply and divide given by conjugate of                            denominator i.e. $\frac{6-4\sqrt{3} }{6-4\sqrt{3} }$

               $=\frac{6-4\sqrt{3} }{6+4\sqrt{3} }* \frac{6-4\sqrt{3} }{6-4\sqrt{3} } \\= \frac{6*6-6*4\sqrt{3}-4\sqrt{3}*6-(4\sqrt{3})^2 }{6^{2} -(4\sqrt{3}) ^{2} }\\=\frac{-12-48\sqrt{3} }{-12}\\\\= -1-4\sqrt{3}$  

Answer:

$-1-4\sqrt{3}$

Hope its clear.

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