Question

rationalize the denominator 6 upon 3 root 2 + 4​

Answer 1

$\implies \sf \dfrac{6}{ 3 {\sqrt{2+4}}}$

Rationalise the denominator.

$\implies \sf \dfrac{\cancel{6}}{\cancel{3}{\sqrt{2+4}}}$

$\implies \sf \dfrac{2}{\sqrt{2+4}}$

$\implies \sf \dfrac{2}{\sqrt{6}}$

$\implies \sf \dfrac{2}{\sqrt{6}} \times \dfrac{\sqrt{6}}{\sqrt{6}}$

$\implies \sf \dfrac{2 \sqrt{6}}{\sqrt{6} {\sqrt{6}}}$

$\implies \sf \dfrac{2 {\sqrt{6}}}{6}$

$\implies \sf \dfrac{{\cancel{2}} \sqrt{6}}{\cancel{6}}$

$\implies \sf \dfrac{\sqrt{6}}{3}$

$\implies \sf \dfrac{2.449}{3}$

$\implies \sf 0.81$