Math, asked by neeleshk832, 19 days ago

rationalize the denominator √7/√8+1​

Answers

Answered by Anonymous
1

 \frac{ \sqrt{7} }{ \sqrt{8}  + 1}  \times  \frac{ \sqrt{8} - 1 }{ \sqrt{8} - 1 }  \\  \\  =  >  \frac{ \sqrt{56} -  \sqrt{7}  }{ {( \sqrt{8} )}^{2} -  {(1)}^{2}  }  \\  \\  =  >  \frac{2 \sqrt{14}  -  \sqrt{7} }{8 - 1}  \\  \\  =  >  \frac{2 \sqrt{14} -  \sqrt{7}  }{7}  =  \frac{2 \sqrt{2} }{ \sqrt{7} }  -  \frac{1}{ \sqrt{7} }

Answered by nakrasameer18
2

Step-by-step explanation:

hope it helps……………………………

plz refer to the attachment

Attachments:
Similar questions