Question

Rationalize the denominator and simplify
$\frac{16}{ \sqrt{41 } - 5}$

Answer 1

HEY!!

HOPE IT HELPS!!

Answer 2

Hey friend,
Here is the answer you were looking for:
$\frac{16}{ \sqrt{41} - 5 }$
On rationalizing the denominator we get,

$= \frac{16}{ \sqrt{41} - 5} \times \frac{ \sqrt{41} + 5 }{ \sqrt{41} + 5 }$

Using the identity:

$(x + y)(x - y) = {x}^{2} - {y}^{2}$

$= \frac{16 \times \sqrt{41} + 16 \times 5 }{ {( \sqrt{41}) }^{2} - {(5)}^{2} } \\ \\ = \frac{16 \sqrt{41} + 80 }{41 - 25} \\ \\ = \frac{16 \sqrt{41} + 80 }{16}$

Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
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