Rationalize the denominator of 1/√2+√3+√10
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=1/(√2+√3)+√10
=1/(√2+√3)+√10×(√2-√3)+√10/(√2-√3)+√10
=√2-√3+√10/(√2)²-(√3)²+√10+√10
=√2-√3+√10/4-3+2√10
=√2-√3/+√10/1+2√10
=√2-√3+√10/1+2√10×1-2√10/1-2√10
=√2-√3+√10×1-2√10/(1)²-(2√10)²
=√2-√3+10
=1/(√2+√3)+√10×(√2-√3)+√10/(√2-√3)+√10
=√2-√3+√10/(√2)²-(√3)²+√10+√10
=√2-√3+√10/4-3+2√10
=√2-√3/+√10/1+2√10
=√2-√3+√10/1+2√10×1-2√10/1-2√10
=√2-√3+√10×1-2√10/(1)²-(2√10)²
=√2-√3+10
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