Rationalize the denominator of 1/(√3 - √2 + 1)
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3
−
2
+1
1
=
(
3
−
2
)+1
1
×
(
3
−
2
)−1
(
3
−
2
)−1
=
(
3
−
2
)
2
−(1)
2
3
−
2
−1
=
(
3
)
2
−2
6
+(
2
)
2
−1
3
−
2
−1
=
3−2
6
+2−1
3
−
2
−1
=
4−2
6
3
−
2
−1
=
2(2−
6
)
(
3
−
2
)−1
=
2(2−
6
)
3
−
2
−1
×
2+
6
2+
6
=
2[(2)
2
−(
6
)
2
]
2
3
−2
2
−2+
18
−
12
−
6
=
2(4−6)
2
3
−2
2
−2+3
2
−2
3
−
6
=
2(−2)
2
−2−
6
=
−4
2
−2−
6
=
4
1
(2+
6
−
2
)
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