Question

rationalize the denominator of 1/√3-√2+1

Answer 1

$\frac{1}{ \sqrt{3} - \sqrt{2} + 1 } = \frac{1}{ \sqrt{3} - \sqrt{2} + 1 } \times \frac{ { \sqrt{3} - \sqrt{2} + 1 }}{ { \sqrt{3} - \sqrt{2} + 1 }} \\ \\ \frac{\sqrt{3} - \sqrt{2} + 1 }{ {( \sqrt{3}) }^{2} - { (\sqrt{2} )}^{2} + 1 } = \frac{\sqrt{3} - \sqrt{2} + 1}{3 - 2 + 1} = \frac{{\sqrt{3} - \sqrt{2} + 1}}{3 - 3}$