:). Rationalize the denominator of 1/√3-√2
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1/✓3-✓2
Denominator is ✓3-✓2
Rationalising factor is ✓3+✓2
1/✓3-✓2 * ✓3+✓2/✓3+✓2
= ✓3+✓2/(✓3-✓2)(✓3+✓2). [Using identity. (a+b)(a-b) = a^2-b^2 ]
= ✓3+✓2/(✓3)^2-(✓2)^2
= ✓3+✓2= 3-2
✓3+✓2/1
✓3+✓2 is the answer
hope it hel you
Answered by
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Answer:hope that it helps u
Step-by-step explanation:
{1/√3-√2}*(√3+√2)/√3+√2
=(√3+√2)/(√3)^2-(√2)^2
=(√3+√2)/3-2
=√3+√2
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