Question

Rationalize the denominator of 1 / root 7 minus root 6

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer :-

To rationalise,

$\frac{1}{ \sqrt{7} - \sqrt{6} }$

We will multiply both the denominator as well as numerator by,

$\sqrt{7} + \sqrt{6}$

Therefore,

$= > \frac{1}{ \sqrt{7} - \sqrt{6} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = > \frac{1 \times \sqrt{7} + \sqrt{6} }{( \sqrt{7} - \sqrt{6}) + ( \sqrt{7} + \sqrt{6} ) } \\ \\ = > \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = > \frac{ \sqrt{7} + \sqrt{6} }{1} = \sqrt{7} + \sqrt{6} \: \: \:$

I hope the answer helps you.