Rationalize the denominator of 3 minus under root 2 upon 3 + under root 2
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3-under root2/3+under root 2
=(3-under root 2)(3-under root2)/(3+under root2)(3-under root2)
By identity asquare-bsquare= (a+b)(a-b)
as well as (a-b) whole square
=9+2-6root2/9-2
=11-6root2/7 is the rationalised form...(as well as the answer)
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