Question

rationalize the denominator of 3/root5-root6​

Answer 1

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Answer 2

Answer:

$\frac{3}{ \sqrt{5 } - \sqrt{6} } \\ = \frac{3( \sqrt{5} + \sqrt{6} )}{( \sqrt{5} - \sqrt{6})( \sqrt{5} + \sqrt{6} )} \\ = \frac{ \sqrt{15} + \sqrt{18} }{( \sqrt{5} ) {}^{2} - ( \sqrt{6} ) {}^{2} } \\ = \frac{ \sqrt{15} + \sqrt{18} }{5 - 6} \\ = \frac{ \sqrt{15} + \sqrt{18} }{ - 1}$